Answer
$4cm$
Work Step by Step
We can find the required height as follows:
$h=\frac{1}{2g}(\frac{m_1+m_2}{m_1-m_2})v_i^2$
We plug in the known values to obtain:
$h=\frac{1}{2(9.81)}(\frac{3.7+4.1}{4.1-3.7})(0.20)^2$
$h=0.04m=4cm$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 8 - Potential Energy and Conservation of Energy - Problems and Conceptual Exercises - Page 247: 37
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