Chapter 5 - Newton's Laws of Motion - Problems and Conceptual Exercises - Page 146: 81

(D) $4.21\times 10^4$ N

We know that $a=\frac{v^2-v_{\circ}^2}{2s}$ We plug in the known values to obtain: $a=\frac{(0m/s)^2-(36m/s)^2}{2(1m)}$ $a=-648m/s^2$ Now $F=(65Kg)(-648m/s^2)$ $F=-4.21\times 10^4N$ Thus, the magnitude of force on the driver is $4.21\times 10^4N$ and hence the correct option is $D$.