Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 5 - Newton's Laws of Motion - Problems and Conceptual Exercises - Page 146: 80

Answer

(C) $2.11\times 10^5 N$

Work Step by Step

We know that $a=\frac{v^2-v_{\circ}^2}{2s}$ We plug in the known values to obtain: $a=\frac{(0m/s)^2-(18m/s)^2}{2(0.05m)}$ $a=-3240m/s^2$ Now the force on the driver can be calculated as: $F=(65Kg)(-3240m/s^2)$ $F=-2.11\times 10^5N$ Thus, the magnitude of force on the driver is $2.11\times 10^5N$ and hence the correct option is $C$.
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