Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 5 - Newton's Laws of Motion - Problems and Conceptual Exercises - Page 144: 56

Answer

$F=60.5N$

Work Step by Step

Force is equal to $F=ma$. To find acceleration, use a kinematics equation involving acceleration, initial velocity, final velocity, and distance. This is $$v_f^2=v_o^2+2a\Delta x$$ Solving for $a$ yields $$a=\frac{v_f^2-v_o^2}{2\Delta x}$$ Substituting known values of $v_o=0.0m/s$, $v_f=36m/s$, and $\Delta x=0.75m$ yields an acceleration of $$a=\frac{(36m/s)^2}{2(0.75m)}=860m/s^2$$ Substituting known values of $a=864m/s^2$ and $m=0.070kg$ yields a force of $$F=(0.070kg)(864m/s^2)=60.5N$$
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