Answer
(a) upward
(b) $1.9m/s^2$
(c) velocity increases when the elevator moves upward and decreases when it moves downward.
Work Step by Step
(a) We know that the weight increases which shows that acceleration of the elevator is upward.
(b) We can calculate the required acceleration of the elevator as follows:
$m=\frac{W}{g}$
$m=\frac{610N}{9.8m/s^2}=62.24Kg$
We know that the net force is given as
$F=W+ma$
$\implies a=\frac{F-W}{m}$
We plug in the known values to obtain:
$a=\frac{730N-610N}{62.24Kg}$
$a=1.9m/s^2$
(c) We know that the velocity of the elevator increases if it moves upward due to increasing acceleration and it decreases when the elevator moves downward.
