Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 5 - Newton's Laws of Motion - Problems and Conceptual Exercises - Page 143: 37

Answer

(a) $0.023~N$ (b) $6.6~days$

Work Step by Step

(a) $1~day=(1~day)(\frac{24~h}{1~day})(\frac{60~s}{1~h})=1.44\times10^3~min$ $\frac{1.6~mg}{min}=(\frac{1.6~mg}{min})(\frac{1~kg}{10^6~mg})(\frac{1.44\times10^3~min}{1~day})=\frac{2.304\times10^{-3}~kg}{day}$ $W=mg=(2.304\times10^{-3}~kg)(9.81~m/s^2)=0.023~N$ (b) $W=mg$ $0.15~N=m(9.81~m/s^2)$ $m=\frac{0.15~N}{9.81~m/s^2}=1.529\times10^{-2}~kg$ $1.529\times10^{-2}~kg=(1.529\times10^{-2}~kg)(\frac{1~day}{2.304\times10^{-3}~kg})=6.6~days$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.