Answer
$0.786m$
Work Step by Step
We can find the required height as follows:
$h=y+\frac{gx^2}{2v_{\circ}^2}$
We plug in the known values to obtain:
$h=0+\frac{(9.81)(1.95)^2}{2(4.87)^2}$
$h=0.786m$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 4 - Two-Dimensional Kinematics - Problems and Conceptual Exercises - Page 108: 63
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