Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 4 - Two-Dimensional Kinematics - Problems and Conceptual Exercises - Page 107: 55

Answer

(a) $213m$ (b) $52.5^{\circ}$

Work Step by Step

(a) We can find the required distance as follows: $R=\frac{v_{\circ}^2}{g}sin2\theta$ We plug in the known values to obtain: $R=\frac{(46.5)^2}{9.81}sin75.0^{\circ}=213m$ (b) We can find the required direction as $\theta=90^{\circ}-37.5^{\circ}=52.5^{\circ}$
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