Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 4 - Two-Dimensional Kinematics - Problems and Conceptual Exercises - Page 104: 4

Answer

(a) $143.34m$ (b) $13.80m$

Work Step by Step

(a) We can find the required horizontal distance traveled as $x=(144m)cos 5.5^{\circ}$ $x=(144m)(0.995396)$ $x=143.34m$ (b) The required vertical distance traveled can be calculated as $y=(144m)sin5.5^{\circ}$ $y=(144m)(0.09584575)$ $y=13.80m$
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