Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 32 - Nuclear Physics and Nuclear Radiation - Problems and Conceptual Exercises - Page 1151: 1

Answer

a) 146 b) 145 c) 84

Work Step by Step

(a) We know that $U^{238}_{92}$ has the following number of particles. $Z=92$, $A=238$ Now $N=A-Z=238-92=146$ (b) For $Pu^{239}_{94}$ $Z=94$, $A=239$ and $N=A-Z=239-94=145$ (c) For $Nd^{144}_{60}$ $Z=60$, $A=144$ and $N=A-Z=144-60=84$
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