Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 31 - Atomic Physics - Problems and Conceptual Exercises - Page 1114: 78

Answer

Please see the work below.

Work Step by Step

(a) We know that $K.E=\frac{ke^2}{r}$ and the total energy is given as $E=\frac{-ke^2}{r}$ $\implies K.E=-E$ $\implies K.E=-(-0.85eV)$ $K.E=0.85eV$ (b) We know that $E=K.E+U$ $\implies -0.85=0.85+U$ $\implies U=-2(0.85)eV$ $\implies U=-1.7eV$
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