Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 31 - Atomic Physics - Problems and Conceptual Exercises - Page 1114: 72

Answer

$3.28\times 10^{15}Hz$

Work Step by Step

We can find the required minimum frequency as follows: $|\Delta E|=|\frac{-13.6}{1^2}|$ $|\Delta E|=(13.6)(1.6\times 10^{-19}J)$ We know that $E=hf$ $\implies hf=(13.6)(1.6\times 10^{-19}J)$ This can be rearranged as: $f=\frac{(13.6)(1.6\times 10^{-19})}{6.63\times 10^{-34}}$ This simplifies to: $f=3.28\times 10^{15}Hz$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.