Answer
$76fm$
Work Step by Step
We can find the required distance as
$K.E=\frac{KqQ}{d}$
This can be rearranged as:
$d=\frac{KqQ}{K.E}$
$d=\frac{K(2e)(79e)}{K.E}$
$d=\frac{158Ke^2}{K.E}$
We plug in the known values to obtain:
$d=\frac{158(8.99\times 10^9)(1.60\times 10^{-19})^2}{(93.0\times 10^6)(1.60\times 10^{-19})}$
$d=76fm$
