Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 31 - Atomic Physics - Problems and Conceptual Exercises - Page 1111: 1

Answer

$8.4\times 10^{-16}$

Work Step by Step

We know that $\frac{V_{nucleus}}{V_{atom}}=\frac{(4/3)\pi r_n^3}{(4/3)\pi r_a^3}$ $\implies \frac{V_{nucleus}}{V_{atom}}=(\frac{r_n}{r_a})^3$ We plug in the known values to obtain: $\frac{V_{nucleus}}{V_{atom}}=(\frac{0.50\times 10^{-15}}{5.3\times 10^{-11}})^3=8.4\times 10^{-16}$
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