Chapter 31 - Atomic Physics - Conceptual Questions - Page 1111: 8

Please see the work below.

(a) We know that there is no upper limit for wavelength $\lambda$. (b) We can find the lower limit as follows: $\frac{1}{\lambda}=R(\frac{1}{(1)^2}-\frac{1}{\infty^2})$ $\implies \lambda=\frac{1}{R}$ $\lambda=\frac{1}{1.097\times 10^7}$ $\lambda=91.2nm$