Answer
(a) $2.81\frac{m}{s}, 1.63\frac{m}{s}$
(b) The direction of velocity will remain the same but its x and y components will be halved.
Work Step by Step
(a) The x and y components of the velocity can be determined as
$v_x=vco\theta$
$\implies v_x=(3.25)cos(30.0^{\circ})=2.81\frac{m}{s}$
similarly $v_y=vsin\theta$
$v_y=(3.25)sin(30.0^{\circ})=1.63\frac{m}{s}$
(b) We know that if the jogger's speed is halved, then the x and y components will be halved but the direction of the velocity will not change.
