Answer
No.
Work Step by Step
Let A be the magnitude of a vector $A$:
A $=\sqrt {(A_x)^2+(A_y)^2}$.
$(A_x)^2$ and $(A_y)^2$ are both nonnegative values. So:
A² $=(A_x)^2+(A_y)^2\geq(A_x)^2$ and
A² $=(A_x)^2+(A_y)^2\geq(A_y)^2$
That is:
A $\gt |A_x|$ and A $\gt |A_y|$
