Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 3 - Vectors in Physics - Conceptual Questions - Page 76: 11

Answer

$\theta=45°$ or $\theta=225°$

Work Step by Step

$\theta=tan^{-1}(\frac{A_y}{A_x})$. If $A_x=-A_y\ne0$: $\theta=tan^{-1}(\frac{A_y}{-A_y})=tan^{-1}(-1)=45°$. Or $\theta=45°+180°=225°$
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