Answer
(A)$~1.01\times 10^{-4}rad$
Work Step by Step
The required linear separation can be determined as
$Linear \space separation=\frac{Height \space of \space screen}{Number \space of \space horizontal \space lines}$
We plug in the known values to obtain:
$Linear\space separation=\frac{15.70}{1080}inch=(\frac{15.70}{1080}inch)(\frac{25.4mm}{1inch})$
$Linear\space separation=0.369mm$
Now $\theta=\frac{linear \space separation}{distance}$
We plug in the known values to obtain:
$\theta=\frac{0.369mm}{12ft}$
$\theta=(\frac{0.369mm}{12ft})(\frac{1ft}{304.8mm})$
$\theta=1.01\times 10^{-4}rad$
