Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 28 - Physical Optics: Interference and Diffraction - Problems and Conceptual Exercises - Page 1008: 76

Answer

Please see the work below.

Work Step by Step

Total path difference $=dsin\theta(\frac{\phi}{2})+dsin(\frac{\phi}{2})=2dsin(\frac{\phi}{2})$ The constructive interference and principal maximum occur when the path difference is an integral multiple of the wavelength $\lambda$. Thus, $2dsin(\frac{\phi}{2})=m\lambda$, where $m=0,\pm1,\pm 2........$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.