Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 27 - Optical Instruments - Problems and Conceptual Exercises - Page 970: 35

Answer

$45cm, 2.2diopters$

Work Step by Step

The focal length can be determined as $f=(\frac{1}{d_{\circ}}-\frac{1}{d_i})^{-1}$ We plug in the known values to obtain: $f=(\frac{1}{25-2.0}+\frac{1}{-(49-2.0)})^{-1}=45cm$ The refractive power can be determined as $refractive power=\frac{1}{f}$ $refractive power=\frac{1}{45cm}=\frac{1}{0.45m}=2.2diopters$
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