Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 27 - Optical Instruments - Problems and Conceptual Exercises - Page 970: 23

Answer

$60.7cm$

Work Step by Step

We can find the required focal length as follows: $\frac{1}{f}=\frac{1}{f_1}+\frac{1}{f_2}$ We plug in the known values to obtain: $\frac{1}{f}=\frac{1}{25.0cm}+\frac{1}{-42.5cm}$ $\frac{1}{f}=\frac{17.5}{1062.5}cm$ $f=\frac{1062.5}{17.5}cm$ $f=60.7cm$
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