Answer
$14.3cm$
Work Step by Step
We can find the eye's nearest point distance as follows:
$d_{\circ}=(\frac{1}{f}-\frac{1}{d_i})^{-1}$
We plug in the known values to obtain:
$d_{\circ}=(\frac{1}{2.20}-\frac{1}{2.60})^{-1}$
$d_{\circ}=14.3cm$