Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 26 - Geometrical Optics - Problems and Conceptual Exercises - Page 946: 128

Answer

a) $d_{\circ}=0.833cm$ b) $d_{\circ}=4.2cm$

Work Step by Step

(a) We know that $\frac{1}{d_{\circ}}+(-\frac{1}{md_{\circ}})=\frac{1}{f}$ We plug in the known values to obtain: $\frac{1}{d_{\circ}}(1-\frac{1}{1.5})=\frac{1}{2.5cm}$ This simplifies to: $d_{\circ}=0.833cm$ (b) We know that $d_i=-md_{\circ}$ $\implies m=-(-1.5)d_{\circ}=1.5d_{\circ}$ As $\frac{1}{d_{\circ}}+\frac{1}{1.5d_{\circ}}=\frac{1}{2.5cm}$ This simplifies to: $d_{\circ}=4.2cm$
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