Answer
$(A)\ 3.25\times 10^{-5}\frac{N}{m^2}$
Work Step by Step
We know that
$P_{avg}=\frac{I_{avg}}{c}$
We plug in the known values to obtain:
$P_{avg}=\frac{0.975W/cm^2\times 10^4cm^2/m^2}{3.00\times 10^8}$
$P_{avg}=3.25\times 10^{-5}\frac{N}{m^2}$
