Answer
(a) $17\Omega$
(b) $14A$
(c) $1.5KW$
Work Step by Step
(a) We can find the impedance as follows:
$Z=\sqrt{R^2+X_L^2}$
We plug in the known values to obtain:
$Z=\sqrt{(7.0\Omega)^2+(15\Omega)^2}$
$Z=17\Omega$
(b) We can find the rms current as
$I_{rms}=\frac{V_{rms}}{Z}$
We plug in the known values to obtain:
$I_{rms}=\frac{240V}{16.6\Omega}$
$I_{rms}=14.4A$
After rounding it off, we obtain:
$I_{rms}=14A$
(c) The average power consumed can be determined as
$P_{avg}=I_{rms}^2R$
We plug in the known values to obtain:
$P_{avg}=(14.4A)^2(7\Omega)$
$P_{avg}=1.5\times 10^3W$
$P_{avg}=1.5KW$
