Answer
$4.0mWb$
Work Step by Step
The magnetic flux through the loop is given as
$\phi=BA_{xy}cos\theta_{xy}+BA_{xz}cos\theta_{xz}=BA(cos\theta_{xy}+cos\theta_{xz})$
We plug in the known values to obtain:
$\phi=(0.035)(0.24)(0.36)(cos65^{\circ}+cos25^{\circ})$
$\phi=4.0mWb$
