Answer
$4.7\times 10^{-10}Wb$
Work Step by Step
We can find the maximum flux as follows:
$\phi_{max}=BAcos\theta$
We plug in the known values to obtain:
$\phi_{max}=(0.15\times 10^{-3})(1.0\times 10^{-3})\pi cos0^{\circ}$
$\phi_{max}=4.7\times 10^{-10}Wb$
