Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 23 - Magnetic Flux and Faraday's Law of Induction - Problems and Conceptual Exercises - Page 833: 75

Answer

Less than

Work Step by Step

The magnetic flux is given as $\phi=BAcos\theta $ When the normal to the loop points horizontally, then the angle between the field and the normal to the loop is $90^{\circ}$. Thus, $\phi_H=BAcos90^{\circ}$ $\phi_H=0$ Similarly, when the normal to the loop points vertically, then the angle between the magnetic field and the normal to the loop is $0^{\circ}$; hence, the flux is $\phi_V=BAcos0^{\circ}$ $\phi_V=BA $ Thus, the magnetic flux when the loop points horizontally is less than the magnetic flux when the loop points vertically downward.
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