Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 23 - Magnetic Flux and Faraday's Law of Induction - Problems and Conceptual Exercises - Page 833: 72

Answer

$2.4KV$

Work Step by Step

We know that $(\frac{N_p}{N_s})=(\frac{V_p}{V_s})=\frac{120}{6.0}=20$ Now $V_p=(V_s)(\frac{N_p}{N_s})=(120)(20)$ $V_p=2.4KV$
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