Answer
$9.75\times 10^{-4}Wb$
Work Step by Step
We can find the magnetic flux as follows:
$\phi=BAcos\theta$
We plug in the known values to obtain:
$\phi=(0.025)(0.325)(0.12)cos0^{\circ}$
$\phi=9.75\times 10^{-4}Wb$
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