Answer
$1.6\times 10^{-4}Wb $
Work Step by Step
We know that
$\phi=BAcos\theta $
$\implies \phi=B\pi r^2cos\theta $
We plug in the known values to obtain:
$\phi=(0.055)\pi(0.031)^2cos16^{\circ}$
$\implies \phi=1.6\times 10^{-4}Wb $
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