Answer
$(c), 2.5\times 10^{-10}A$
Work Step by Step
We know that
$I=\frac{2\pi rB}{\mu_{\circ}}$
We plug in the known values to obtain:
$I=\frac{2\pi(0.050)(1.0\times 10^{-15})}{4\pi\times 10^{-7}}$
$I=2.5\times 10^{-10}$
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