Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 22 - Magnetism - Problems and Conceptual Exercises - Page 799: 107

Answer

$(c), 2.5\times 10^{-10}A$

Work Step by Step

We know that $I=\frac{2\pi rB}{\mu_{\circ}}$ We plug in the known values to obtain: $I=\frac{2\pi(0.050)(1.0\times 10^{-15})}{4\pi\times 10^{-7}}$ $I=2.5\times 10^{-10}$
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