Answer
$I=2.6KA$
Work Step by Step
We know that
$I=\frac{BL}{\mu_{\circ}N}=\frac{BL}{\mu_{\circ}(L/d)}$
$\implies I=\frac{Bd}{\mu_{\circ}}$
We plug in the known values to obtain:
$I=\frac{(1.5)(0.0022)}{4\pi\times 10^{-7}}$
$I=2.6KA$
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