Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 22 - Magnetism - Problems and Conceptual Exercises - Page 796: 73

Answer

$7.0\mu m$

Work Step by Step

We know that $r=\frac{\mu_{\circ}}{2\pi B}$ We plug in the known values to obtain: $r=\frac{(4\pi \times 10^{-7})(3.5)}{2\pi (0.10)}$ $r=7.0\times 10^{-6}=7.0\mu m$
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