Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 22 - Magnetism - Problems and Conceptual Exercises - Page 796: 69

Answer

$F=0$ N

Work Step by Step

We know that $F=qvBsin\theta$ We plug in the known values to obtain: $F=1.6\times 10^{-19}(0)(0.35)sin\theta$ $F=0$ N
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