Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 21 - Electric Current and Direct-Current Circuits - Problems and Conceptual Exercises - Page 761: 111

Answer

$R_1=18\Omega;R_2=62\Omega$

Work Step by Step

We can find the required resistances of the two resistors as follows: Given that both resistors are in series so $R_1=\frac{2.7V}{0.15A}=18\Omega$ Now the equivalent resistance is $R_{eq}=R_1+R_2$ $\implies \frac{V}{I}=R_1+R_2$ $\implies R_2=\frac{V}{I}-R_1$ We plug in the known values to obtain: $R_2=\frac{12V}{0.15A}-18\Omega$ $R_2=62\Omega$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.