Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 21 - Electric Current and Direct-Current Circuits - Problems and Conceptual Exercises - Page 761: 105

Answer

$0.54V$

Work Step by Step

We know that $V=IR$ $\implies V=I\rho \frac{L}{A}$ We plug in the known values to obtain: $V=\frac{(5.0A)(1.72\times 10^{-8}\Omega.m)(12ft)(\frac{0.3048m}{1ft})}{1.17\times 10^{-6}m^2}$ $V=0.54V$
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