Answer
(a) decrease
(b) $I=0.12A$; clockwise
Work Step by Step
(a) We know that both the batteries in the circuit are in opposite direction, thus their net emf decreases and as a result the current will decrease.
(b) According to Kirchhoff's Mesh rule
$I(8.50\Omega)+I(6.22\Omega)+I(15.1\Omega)=15.0V-11.5V$
This simplifies to:
$I=\frac{3.5V}{29.82\Omega}$
$I=0.12A$
The positive value of the current shows that the current flows in clockwise direction.
