Answer
$0.16KV$
Work Step by Step
As the resistors are connected in series so
$R_{eq}=89+130=219\Omega$
Now we can find the emf as
$V=IR_{eq}$
We plug in the known values to obtain:
$V=(0.72)(219)$
$V=157.68V=0.16KV$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 21 - Electric Current and Direct-Current Circuits - Problems and Conceptual Exercises - Page 756: 47
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