Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 21 - Electric Current and Direct-Current Circuits - Problems and Conceptual Exercises - Page 755: 30

Answer

$\$0.0234$

Work Step by Step

We know that $P=VI$ $\implies P=120\times 2.6=312W$ We can now find energy consumed per hour as $E=P\times t$ $\implies E=312\times 1=312W.hr=0.312KW.hr$ As given that for 1 khw.hr, the cost is $\$0.075$ Thus cost for $0.312KW.hr$ is $0.075\times 0.312=\$0.0234$
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