Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 21 - Electric Current and Direct-Current Circuits - Problems and Conceptual Exercises - Page 755: 25

Answer

(a) bulb A (b) 4

Work Step by Step

(a) We know that power and voltage are related as $P=VI$ $\implies P_A=4P_B$ $\implies VI_A=4VI_B$ $\implies I_A=4I_B$ Thus, the bulb A has the greater current passing through it. (b) We know that power and voltage are related as $P=VI$ $\implies P_A=4P_B$ $\implies VI_A=4VI_B$ $\implies I_A=4I_B$ $\implies \frac{I_A}{I_B}=4 $ This is the required ratio.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.