Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 21 - Electric Current and Direct-Current Circuits - Problems and Conceptual Exercises - Page 755: 15

Answer

$0.68K\Omega$

Work Step by Step

We know that $R=\frac{\rho L}{A}$ $\implies R=\frac{4\rho L}{\pi D^2}$ We plug in the known values to obtain: $R=\frac{4(1.68\times 10^{-8})(9654)}{\pi(0.55\times 10^{-3})^2}$ $R=0.68K\Omega$
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