Answer
$0.68K\Omega$
Work Step by Step
We know that
$R=\frac{\rho L}{A}$
$\implies R=\frac{4\rho L}{\pi D^2}$
We plug in the known values to obtain:
$R=\frac{4(1.68\times 10^{-8})(9654)}{\pi(0.55\times 10^{-3})^2}$
$R=0.68K\Omega$
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