Answer
$R=0.49 \Omega$
Work Step by Step
We know that
$R=\rho \frac{L}{A}$
$\implies R=\frac{\rho L}{\frac{\pi}{4}D^2}$
$R=\frac{4\rho L}{\pi D^2}$
We plug in the known values to obtain:
$R=\frac{4(1.59\times 10^{-8})(5.9)}{\pi(0.49\times 10^{-3})^2}$
$R=0.49 \Omega$