Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 20 - Electric Potential and Electric Potential Energy - Problems and Conceptual Exercises - Page 719: 43

Answer

(a) greater than (b) III

Work Step by Step

(a) We know that $E=-\frac{\Delta V}{\Delta s}$. As E points towards the right, the voltage difference is $V_3-V_1<0$. This shows that potential 1 greater than potential 3 because the electric potential decreases in the direction of the electric field. (b) Option III is correct. That is, the electric field is more intense at point 2 than at point 1, which means that the equipotential surfaces are more closely spaced in the region.
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