Answer
(a) $0.0100~s=10.0~ms$
(b) $4.50~m/s$
(c) $0.100~m=10.0~cm$
Work Step by Step
(a) We can find the required time as
$t=\frac{v_{\circ}}{a_1-a_2}$
We plug in the known values to obtain:
$t=\frac{20.0m/s}{450m/s^2+1550m/s^2}$
$t=10.0ms$
(b) We know that
$v=a_1t$
We plug in the known values to obtain:
$v=(450m/s^2)(0.01s)$
$v=4.50m/s$
(c) As $d=v_{\circ}t+\frac{1}{2}a_2t^2$
We plug in the known values to obtain:
$d=(20.0m)(0.01s)-\frac{1}{2}(1550m/s^2)(0.01s)$
$d=0.10m=10.0cm$
