Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 2 - One-Dimensional Kinematics - Problems and Conceptual Exercises - Page 51: 50

Answer

$a_{av}=9.1~m/s^2$

Work Step by Step

We can find the required average acceleration as follows: $v_f=45mi/h$ $v_f=\frac{45\times 1.609\times 10^3m}{3600s}$ $v_f=20.1m/s$ Now $a=\frac{v_f-v_i}{t}$ We plug in the known values to obtain: $a=\frac{20.1m/s-0m/s}{2.2s}$ $a=9.1m/s^2$
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