Chapter 2 - One-Dimensional Kinematics - Problems and Conceptual Exercises - Page 48: 9

Average speed $=10.1 m/s=22.66 mi/h$

We know that $v=\frac{s}{t}$ We plug in the known values to obtain: $v=\frac{200m}{19.75s}$ $v=10.1m/s$ Now $v=(10.1m/s)(\frac{3600s}{1h})(\frac{1mile}{1.61\times 10^3m})$ $v=22.66mi/h$