Answer
Average speed $=1.83 m/s=4.09mi/h$
Work Step by Step
We know that
$v=\frac{s}{t}$
$\implies v=\frac{100m}{54.64s}=1.83m/s$
Now $v=(1.83m/s)(\frac{3600s}{1h})(\frac{1mile}{1.61\times 10^3m})$
$v=4.09miles/h$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 2 - One-Dimensional Kinematics - Problems and Conceptual Exercises - Page 48: 10
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