Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 19 - Electric Charges, Forces, and Fields - Problems and Conceptual Exercises - Page 688: 93

Answer

(a) $5.71\times 10^{13}C$ (b) no change

Work Step by Step

(a) We can find the values of Q as follows: $\frac{GM_EM_M}{R^2}=\frac{KQ^2}{R^2}$ This simplifies to: $Q=\sqrt{\frac{GM_EM_M}{K}}$ We plug in the known values to obtain: $Q=\sqrt{\frac{(6.67\times 10^{-11})(5.97\times 10^{24})(7.35\times 10^{22})}{8.99\times 10^9}}$ $Q=5.71\times 10^{13}C$ (b) From part (a): $Q=\sqrt{\frac{GM_EM_M}{K}}$. This equation shows us that the Q value does not depend on the distance. Thus, if the distance is doubled, the answer to part (a) does not change.
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